std::swap_ranges
From cppreference.com
Defined in header <algorithm> | ||
(1) | ||
template<class ForwardIt1, class ForwardIt2 > ForwardIt2 swap_ranges( ForwardIt1 first1, ForwardIt1 last1, | (until C++20) | |
template<class ForwardIt1, class ForwardIt2 > constexpr ForwardIt2 swap_ranges( ForwardIt1 first1, ForwardIt1 last1, | (since C++20) | |
template<class ExecutionPolicy, class ForwardIt1, class ForwardIt2 > ForwardIt2 swap_ranges( ExecutionPolicy&& policy, | (2) | (since C++17) |
1) Exchanges elements between range
[first1, last1)
and another range starting at first2
. 2) Same as (1), but executed according to
policy
. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is trueContents |
[edit]Parameters
first1, last1 | - | the first range of elements to swap |
first2 | - | beginning of the second range of elements to swap |
policy | - | the execution policy to use. See execution policy for details. |
Type requirements | ||
-ForwardIt1, ForwardIt2 must meet the requirements of LegacyForwardIterator. | ||
-The types of dereferenced ForwardIt1 and ForwardIt2 must meet the requirements of Swappable |
[edit]Return value
Iterator to the element past the last element exchanged in the range beginning with first2
.
[edit]Exceptions
The overload with a template parameter named ExecutionPolicy
reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
[edit]Possible implementation
template<class ForwardIt1, class ForwardIt2>constexpr ForwardIt2 swap_ranges(ForwardIt1 first1, ForwardIt1 last1, ForwardIt2 first2){while(first1 != last1){std::iter_swap(first1++, first2++);}return first2;} |
[edit]Example
Demonstrates swapping of subranges from different containers
Run this code
#include <algorithm>#include <list>#include <vector>#include <iostream>int main(){std::vector<int> v ={1, 2, 3, 4, 5};std::list<int> l ={-1, -2, -3, -4, -5}; std::swap_ranges(v.begin(), v.begin()+3, l.begin()); for(int n : v)std::cout<< n <<' ';std::cout<<'\n';for(int n : l)std::cout<< n <<' ';std::cout<<'\n';}
Output:
-1 -2 -3 4 5 1 2 3 -4 -5
[edit]Complexity
linear in the distance between first1
and last1
[edit]See also
swaps the elements pointed to by two iterators (function template) | |
swaps the values of two objects (function template) |