std::accumulate
Defined in header <numeric> | ||
template<class InputIt, class T > T accumulate( InputIt first, InputIt last, T init ); | (1) | |
template<class InputIt, class T, class BinaryOperation > T accumulate( InputIt first, InputIt last, T init, | (2) | |
Computes the sum of the given value init
and the elements in the range [first, last)
. The first version uses operator+
to sum up the elements, the second version uses the given binary function op
, both applying std::move to their operands on the left hand side(since C++20).
| (until C++11) |
| (since C++11) |
Contents |
[edit]Parameters
first, last | - | the range of elements to sum |
init | - | initial value of the sum |
op | - | binary operation function object that will be applied. The binary operator takes the current accumulation value a (initialized to init ) and the value of the current element b . The signature of the function should be equivalent to the following: Ret fun(const Type1 &a, const Type2 &b); The signature does not need to have const&. |
Type requirements | ||
-InputIt must meet the requirements of LegacyInputIterator. | ||
-T must meet the requirements of CopyAssignable and CopyConstructible. |
[edit]Return value
[edit]Notes
std::accumulate
performs a left fold. In order to perform a right fold, one must reverse the order of the arguments to the binary operator, and use reverse iterators.
[edit]Possible implementation
First version |
---|
template<class InputIt, class T> T accumulate(InputIt first, InputIt last, T init){for(; first != last;++first){ init = std::move(init)+*first;// std::move since C++20}return init;} |
Second version |
template<class InputIt, class T, class BinaryOperation> T accumulate(InputIt first, InputIt last, T init, BinaryOperation op){for(; first != last;++first){ init = op(std::move(init), *first);// std::move since C++20}return init;} |
[edit]Example
#include <iostream>#include <vector>#include <numeric>#include <string>#include <functional> int main(){std::vector<int> v{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; int sum = std::accumulate(v.begin(), v.end(), 0); int product = std::accumulate(v.begin(), v.end(), 1, std::multiplies<int>()); auto dash_fold =[](std::string a, int b){return std::move(a)+'-'+std::to_string(b);}; std::string s = std::accumulate(std::next(v.begin()), v.end(), std::to_string(v[0]), // start with first element dash_fold); // Right fold using reverse iteratorsstd::string rs = std::accumulate(std::next(v.rbegin()), v.rend(), std::to_string(v.back()), // start with last element dash_fold); std::cout<<"sum: "<< sum <<'\n'<<"product: "<< product <<'\n'<<"dash-separated string: "<< s <<'\n'<<"dash-separated string (right-folded): "<< rs <<'\n';}
Output:
sum: 55 product: 3628800 dash-separated string: 1-2-3-4-5-6-7-8-9-10 dash-separated string (right-folded): 10-9-8-7-6-5-4-3-2-1
[edit]See also
computes the differences between adjacent elements in a range (function template) | |
computes the inner product of two ranges of elements (function template) | |
computes the partial sum of a range of elements (function template) | |
(C++17) | similar to std::accumulate, except out of order (function template) |