std::set_intersection
![]() | Questa pagina è stata tradotta in modo automatico dalla versione in ineglese della wiki usando Google Translate. La traduzione potrebbe contenere errori e termini strani. Muovi il puntatore sopra al testo per vedere la versione originale. Puoi aiutarci a correggere gli gli errori. Per ulteriori istruzioni clicca qui. |
Defined in header <algorithm> | ||
template<class InputIt1, class InputIt2, class OutputIt > OutputIt set_intersection( InputIt1 first1, InputIt1 last1, | (1) | |
template<class InputIt1, class InputIt2, class OutputIt, class Compare > | (2) | |
d_first
costituito da elementi che si trovano in entrambe le gamme filtrate [first1, last1)
e [first2, last2)
. La prima versione si aspetta che sia l'ingresso che varia da ordinare con operator<, la seconda versione si aspetta che essere ordinati con il confronto comp
data funzione. Se qualche elemento si trova m
volte in [first1, last1)
e n
volte [first2, last2)
, gli elementi std::min(m, n) primo verranno copiati dalla prima serie alla gamma di destinazione. L'ordine degli elementi equivalenti è conservato. L'intervallo risultante non possono sovrapporsi uno dei campi di ingresso.d_first
consisting of elements that are found in both sorted ranges [first1, last1)
and [first2, last2)
. The first version expects both input ranges to be sorted with operator<, the second version expects them to be sorted with the given comparison function comp
. If some element is found m
times in [first1, last1)
and n
times in [first2, last2)
, the first std::min(m, n) elements will be copied from the first range to the destination range. The order of equivalent elements is preserved. The resulting range cannot overlap with either of the input ranges.You can help to correct and verify the translation. Click here for instructions.
Indice |
[modifica]Parametri
first1, last1 | - | la prima gamma di elementi da esaminare Original: the first range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
first2, last2 | - | il secondo intervallo di elementi da esaminare Original: the second range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); The signature does not need to have const&, but the function must not modify the objects passed to it. |
Type requirements | ||
-InputIt1 must meet the requirements of InputIterator . | ||
-InputIt2 must meet the requirements of InputIterator . | ||
-OutputIt must meet the requirements of OutputIterator . |
[modifica]Valore di ritorno
You can help to correct and verify the translation. Click here for instructions.
[modifica]Complessità
You can help to correct and verify the translation. Click here for instructions.
[modifica]Possibile implementazione
First version |
---|
template<class InputIt1, class InputIt2, class OutputIt> OutputIt set_intersection(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first){while(first1 != last1 && first2 != last2){if(*first1 <*first2){++first1;}else{if(!(*first2 <*first1)){*d_first++=*first1++;}++first2;}}return d_first;} |
Second version |
template<class InputIt1, class InputIt2, class OutputIt, class Compare> OutputIt set_intersection(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp){while(first1 != last1 && first2 != last2){if(comp(*first1, *first2)){++first1;}else{if(!comp(*first2, *first1)){*d_first++=*first1++;}++first2;}}return d_first;} |
[modifica]Esempio
#include <iostream>#include <vector>#include <algorithm>#include <iterator>int main(){std::vector<int> v1{1,2,3,4,5,6,7,8};std::vector<int> v2{5, 7, 9,10};std::sort(v1.begin(), v1.end());std::sort(v2.begin(), v2.end()); std::vector<int> v_intersection; std::set_intersection(v1.begin(), v1.end(), v2.begin(), v2.end(), std::back_inserter(v_intersection));for(int n : v_intersection)std::cout<< n <<' ';}
Output:
5 7
[modifica]Vedi anche
computes the union of two sets (funzione di modello) |