std::max
From cppreference.com
Defined in header <algorithm> | ||
(1) | ||
template<class T > const T& max(const T& a, const T& b ); | (until C++14) | |
template<class T > constexprconst T& max(const T& a, const T& b ); | (since C++14) | |
(2) | ||
template<class T, class Compare > const T& max(const T& a, const T& b, Compare comp ); | (until C++14) | |
template<class T, class Compare > constexprconst T& max(const T& a, const T& b, Compare comp ); | (since C++14) | |
(3) | ||
template<class T > T max(std::initializer_list<T> ilist ); | (since C++11) (until C++14) | |
template<class T > constexpr T max(std::initializer_list<T> ilist ); | (since C++14) | |
(4) | ||
template<class T, class Compare > T max(std::initializer_list<T> ilist, Compare comp ); | (since C++11) (until C++14) | |
template<class T, class Compare > constexpr T max(std::initializer_list<T> ilist, Compare comp ); | (since C++14) | |
Returns the greater of the given values.
1-2) Returns the greater of
a
and b
. 3-4) Returns the greatest of the values in initializer list
ilist
.The (1,3) versions use operator< to compare the values, the (2,4) versions use the given comparison function comp
.
Contents |
[edit]Parameters
a, b | - | the values to compare |
ilist | - | initializer list with the values to compare |
comp | - | comparison function object (i.e. an object that satisfies the requirements of Compare ) which returns true if a is less than b . The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); The signature does not need to have const&, but the function object must not modify the objects passed to it. |
Type requirements | ||
-T must meet the requirements of LessThanComparable in order to use overloads (1,3). | ||
-T must meet the requirements of CopyConstructible in order to use overloads (3,4). |
[edit]Return value
1-2) The greater of
a
and b
. If they are equivalent, returns a
.3-4) The greatest value in
ilist
. If several values are equivalent to the greatest, returns the leftmost one.[edit]Complexity
1-2) Exactly one comparison
3-4) Exactly
ilist.size() - 1
comparisons[edit]Possible implementation
First version |
---|
template<class T>const T& max(const T& a, const T& b){return(a < b)? b : a;} |
Second version |
template<class T, class Compare>const T& max(const T& a, const T& b, Compare comp){return(comp(a, b))? b : a;} |
Third version |
template<class T > T max(std::initializer_list<T> ilist){return*std::max_element(ilist.begin(), ilist.end());} |
Fourth version |
template<class T, class Compare > T max(std::initializer_list<T> ilist, Compare comp ){return*std::max_element(ilist.begin(), ilist.end(), comp);} |
[edit]Notes
Capturing the result of std::max
by reference if one of the parameters is rvalue produces a dangling reference if that parameter is returned:
int n =1;constint& r = std::max(n-1, n+1);// r is dangling
[edit]Example
Run this code
#include <algorithm>#include <iostream>#include <string> int main(){std::cout<<"larger of 1 and 9999: "<< std::max(1, 9999)<<'\n'<<"larger of 'a', and 'b': "<< std::max('a', 'b')<<'\n'<<"longest of \"foo\", \"bar\", and \"hello\": "<< std::max({"foo", "bar", "hello"}, [](conststd::string& s1, conststd::string& s2){return s1.size()< s2.size();})<<'\n';}
Output:
larger of 1 and 9999: 9999 larger of 'a', and 'b': b longest of "foo", "bar", and "hello": hello
[edit]See also
returns the smaller of the given values (function template) | |
(C++11) | returns the smaller and larger of two elements (function template) |
returns the largest element in a range (function template) |