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std::unique_copy

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< cpp‎ | algorithm

 
 
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ヘッダ <algorithm> で定義
template<class InputIt, class OutputIt >

ForwardIt unique_copy( InputIt first, InputIt last,

                       OutputIt d_first );
(1)
template<class InputIt, class OutputIt, class BinaryPredicate >

ForwardIt unique_copy( InputIt first, InputIt last,

                       OutputIt d_first, BinaryPredicate p );
(2)
全く連続した等しい要素が存在しないような方法で[first, last)から始まる別の範囲に、範囲d_firstから要素をコピーします。のみ等しい要素の各グループの最初の要素がコピーされます。最初のバージョンは、要素を比較するoperator==使用して、2番目のバージョンは、指定されたバイナリ述語pを使用しています.
Original:
Copies the elements from the range [first, last), to another range beginning at d_first in such a way that there are no consecutive equal elements. Only the first element of each group of equal elements is copied. The first version uses operator== to compare the elements, the second version uses the given binary predicate p.
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目次

[編集]パラメータ

first, last -
プロセスへの要素の範囲
Original:
the range of elements to process
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d_first -
目的の範囲の始まり
Original:
the beginning of the destination range
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p - binary predicate which returns ​true if the elements should be treated as equal.

The signature of the predicate function should be equivalent to the following:

 bool pred(const Type1 &a, const Type2 &b);

The signature does not need to have const&, but the function must not modify the objects passed to it.
The types  Type1 and  Type2 must be such that an object of type ForwardIt can be dereferenced and then implicitly converted to both of them.

型の要件
-
InputItInputIterator

の要求を満足しなければなりません。

-
OutputItOutputIterator

の要求を満足しなければなりません。

-
The type of dereferenced InputIt must meet the requirements of CopyAssignable.
-
The type of dereferenced InputIt must meet the requirements of CopyConstructible. if neither InputIt nor OutputIt satisfies ForwardIterator

[編集]値を返します

最後に書き込まれた要素過去の要素への出力イテレータ
Original:
Output iterator to the element past the last written element
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[編集]可能な実装

First version
template<class ForwardIt, class OutputIt> ForwardIt unique_copy(ForwardIt first, ForwardIt last, OutputIt d_first){   if(first == last)return d_first;   *d_first =*first;while(++first != last){if(!(*d_first ==*first)){*(++d_first)=*first;}}return++d_first;}
Second version
template<class ForwardIt, class OutputIt, class BinaryPredicate> ForwardIt unique_copy(ForwardIt first, ForwardIt last, OutputIt d_first, BinaryPredicate p){   if(first == last)return d_first;   *d_first =*first;while(++first != last){if(!p(*result, *first)){*(++d_first)=*first;}}return++d_first;}

[編集]

次のプログラムのトリムconst文字列内のすべての連続する複数のスペースを、その結果を出力します
Original:
The following program trims all multiple consecutive spaces in a const string and prints the result
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#include <string>#include <iostream>#include <algorithm>#include <iterator>   int main(){std::string s1 ="The string with many spaces!";std::cout<<"before: "<< s1 <<'\n';   std::string s2; std::unique_copy(s1.begin(), s1.end(), std::back_inserter(s2), [](char c1, char c2){return c1 ==' '&& c2 ==' ';});   std::cout<<"after: "<< s2 <<'\n';}

出力:

before: The string with many spaces! after: The string with many spaces!

[編集]複雑性

firstlastとの間の距離の線形
Original:
linear in the distance between first and last
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[編集]参照

互いに隣接する2つの同一の(またはいくつかの他の関係)のアイテムを見つけることができます
Original:
finds two identical (or some other relationship) items adjacent to each other
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(関数テンプレート)[edit]
ある範囲内で連続して重複している要素を取り除きます
(関数テンプレート)[edit]
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