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std::set_difference

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< cpp‎ | algorithm

 
 
アルゴリズムライブラリ
機能します
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Functions
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シーケンス動作を非改変
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Non-modifying sequence operations
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シーケンス動作を変更する
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Modifying sequence operations
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操作を仕切る
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Partitioning operations
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(ソートされた範囲で)ソート操作
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Sorting operations (on sorted ranges)
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バイナリ検索操作(ソート範囲で)
Original:
Binary search operations (on sorted ranges)
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(ソートされた範囲で)操作を設定します
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Set operations (on sorted ranges)
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ヒープ操作
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Heap operations
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最小値/最大値操作
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Minimum/maximum operations
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数値演算
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Numeric operations
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Cライブラリ
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C library
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Defined in header <algorithm>
template<class InputIt1, class InputIt2, class OutputIt >

OutputIt set_difference( InputIt1 first1, InputIt1 last1,
                         InputIt2 first2, InputIt2 last2,

                         OutputIt d_first );
(1)
template<class InputIt1, class InputIt2,

          class OutputIt, class Compare >
OutputIt set_difference( InputIt1 first1, InputIt1 last1,
                         InputIt2 first2, InputIt2 last2,

                         OutputIt d_first, Compare comp );
(2)
ソート範囲[first1, last1)で発見されていないソート範囲[first2, last2)からd_firstで範囲の先頭に要素をコピーします.
Original:
Copies the elements from the sorted range [first1, last1) which are not found in the sorted range [first2, last2) to the range beginning at d_first.
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結果として得られる範囲は、またソートされます。最初のバージョンでは、両方の入力がoperator<でソートされている範囲では、2番目のバージョンは、それらが与えられた比較関数compでソートされることを想定して期待しています。いくつかの要素がm[first1, last1)n[first2, last2)倍であることが判明した場合、同等の要素があること、個別に扱われ、それが正確にd_firststd::max(m-n, 0)倍にコピーされます。結果の範囲は入力レンジのいずれかと重複することはできません.
Original:
The resulting range is also sorted. The first version expects both input ranges to be sorted with operator<, the second version expects them to be sorted with the given comparison function comp. Equivalent elements are treated individually, that is, if some element is found m times in [first1, last1) and n times in [first2, last2), it will be copied to d_first exactly std::max(m-n, 0) times. The resulting range cannot overlap with either of the input ranges.
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目次

[編集]パラメータ

first1, last1 -
検討する要素の範囲
Original:
the range of elements to examine
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first2, last2 -
検索する要素の範囲
Original:
the range of elements to search for
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comp - 比較関数. 最初の値が二つ目の値より小さい 場合、 ​trueを返します.

比較関数のシグネチャは以下と同等でなければなりません.

 bool cmp(const Type1 &a, const Type2 &b);

シグネチャはconstを含まなくても構いませんが, 比較関数は渡されたオブジェクトを変更してはなりません.
The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively. ​

型の要件
-
InputIt1InputIterator

の要求を満足しなければなりません。

-
InputIt2InputIterator

の要求を満足しなければなりません。

-
OutputItOutputIterator

の要求を満足しなければなりません。

[編集]値を返します

構築範囲の終わり過去イテレータ.
Original:
Iterator past the end of the constructed range.
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[編集]複雑性

最も2·(N1+N2-1)の比較で、どこN1=std::distance(first1, last1)N2=std::distance(first2, last2).
Original:
At most 2·(N1+N2-1) comparisons, where N1=std::distance(first1, last1) and N2=std::distance(first2, last2).
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[編集]可能な実装

First version
template<class InputIt1, class InputIt2, class OutputIt> OutputIt set_difference(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first){while(first1 != last1){if(first2 == last2)returnstd::copy(first1, last1, d_first);   if(*first1 <*first2){*d_first++=*first1++;}else{if(!(*first2 <*first1)){++first1;}++first2;}}return d_first;}
Second version
template<class InputIt1, class InputIt2, class OutputIt, class Compare> OutputIt set_difference( InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp){while(first1 != last1){if(first2 == last2)returnstd::copy(first1, last1, d_first);   if(comp(*first1, *first2)){*d_first++=*first1++;}else{if(!comp(*first2, *first1)){++first1;}++first2;}}return d_first;}

[編集]

#include <iostream>#include <algorithm>#include <vector>#include <iterator>   int main(){std::vector<int> v1 {1, 2, 5, 5, 5, 9};std::vector<int> v2 {2, 5, 7};std::vector<int> diff;   std::set_difference(v1.begin(), v1.end(), v2.begin(), v2.end(), std::inserter(diff, diff.begin()));   for(auto i : v1)std::cout<< i <<' ';std::cout<<"minus ";for(auto i : v2)std::cout<< i <<' ';std::cout<<"is: ";   for(auto i : diff)std::cout<< i <<' ';std::cout<<'\n';}

出力:

1 2 5 5 5 9 minus 2 5 7 is: 1 5 5 9

[編集]参照

1セットが他のサブセットである場合はtrueを返します
Original:
returns true if one set is a subset of another
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(関数テンプレート)[edit]
2セット間の対称差を計算します
Original:
computes the symmetric difference between two sets
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(関数テンプレート)[edit]
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