Contents
LLVM avoids using C++'s built in RTTI. Instead, it pervasively uses its own hand-rolled form of RTTI which is much more efficient and flexible, although it requires a bit more work from you as a class author.
A description of how to use LLVM-style RTTI from a client's perspective is given in the Programmer's Manual. This document, in contrast, discusses the steps you need to take as a class hierarchy author to make LLVM-style RTTI available to your clients.
Before diving in, make sure that you are familiar with the Object Oriented Programming concept of "is-a".
This section describes how to set up the most basic form of LLVM-style RTTI (which is sufficient for 99.9% of the cases). We will set up LLVM-style RTTI for this class hierarchy:
classShape { public:Shape() {} virtualdoublecomputeArea() = 0; }; classSquare : publicShape { double SideLength; public:Square(double S) : SideLength(S) {} doublecomputeArea() override; }; classCircle : publicShape { double Radius; public:Circle(double R) : Radius(R) {} doublecomputeArea() override; };
The most basic working setup for LLVM-style RTTI requires the following steps:
In the header where you declare
Shape
, you will want to#include "llvm/Support/Casting.h"
, which declares LLVM's RTTI templates. That way your clients don't even have to think about it.#include"llvm/Support/Casting.h"
In the base class, introduce an enum which discriminates all of the different concrete classes in the hierarchy, and stash the enum value somewhere in the base class.
Here is the code after introducing this change:
classShape { public: + /// Discriminator for LLVM-style RTTI (dyn_cast<> et al.) + enum ShapeKind { + SK_Square, + SK_Circle + }; +private: + const ShapeKind Kind; +public: + ShapeKind getKind() const { return Kind; } + Shape() {} virtualdoublecomputeArea() = 0; };
You will usually want to keep the
Kind
member encapsulated and private, but let the enumShapeKind
be public along with providing agetKind()
method. This is convenient for clients so that they can do aswitch
over the enum.A common naming convention is that these enums are "kind"s, to avoid ambiguity with the words "type" or "class" which have overloaded meanings in many contexts within LLVM. Sometimes there will be a natural name for it, like "opcode". Don't bikeshed over this; when in doubt use
Kind
.You might wonder why the
Kind
enum doesn't have an entry forShape
. The reason for this is that sinceShape
is abstract (computeArea() = 0;
), you will never actually have non-derived instances of exactly that class (only subclasses). See Concrete Bases and Deeper Hierarchies for information on how to deal with non-abstract bases. It's worth mentioning here that unlikedynamic_cast<>
, LLVM-style RTTI can be used (and is often used) for classes that don't have v-tables.Next, you need to make sure that the
Kind
gets initialized to the value corresponding to the dynamic type of the class. Typically, you will want to have it be an argument to the constructor of the base class, and then pass in the respectiveXXXKind
from subclass constructors.Here is the code after that change:
classShape { public:/// Discriminator for LLVM-style RTTI (dyn_cast<> et al.)enum ShapeKind { SK_Square, SK_Circle }; private:const ShapeKind Kind; public: ShapeKind getKind() const { return Kind; } - Shape() {} + Shape(ShapeKind K) : Kind(K) {} virtualdoublecomputeArea() = 0; }; classSquare : publicShape { double SideLength; public: - Square(double S) : SideLength(S) {} + Square(double S) : Shape(SK_Square), SideLength(S) {} doublecomputeArea() override; }; classCircle : publicShape { double Radius; public: - Circle(double R) : Radius(R) {} + Circle(double R) : Shape(SK_Circle), Radius(R) {} doublecomputeArea() override; };
Finally, you need to inform LLVM's RTTI templates how to dynamically determine the type of a class (i.e. whether the
isa<>
/dyn_cast<>
should succeed). The default "99.9% of use cases" way to accomplish this is through a small static member functionclassof
. In order to have proper context for an explanation, we will display this code first, and then below describe each part:classShape { public:/// Discriminator for LLVM-style RTTI (dyn_cast<> et al.)enum ShapeKind { SK_Square, SK_Circle }; private:const ShapeKind Kind; public: ShapeKind getKind() const { return Kind; } Shape(ShapeKind K) : Kind(K) {} virtualdoublecomputeArea() = 0; }; classSquare : publicShape { double SideLength; public:Square(double S) : Shape(SK_Square), SideLength(S) {} doublecomputeArea() override; + + staticboolclassof(const Shape *S) { + return S->getKind() == SK_Square; + } }; classCircle : publicShape { double Radius; public:Circle(double R) : Shape(SK_Circle), Radius(R) {} doublecomputeArea() override; + + staticboolclassof(const Shape *S) { + return S->getKind() == SK_Circle; + } };
The job of
classof
is to dynamically determine whether an object of a base class is in fact of a particular derived class. In order to downcast a typeBase
to a typeDerived
, there needs to be aclassof
inDerived
which will accept an object of typeBase
.To be concrete, consider the following code:
Shape *S = ...; if (isa<Circle>(S)) { /* do something ... */ }
The code of the
isa<>
test in this code will eventually boil down---after template instantiation and some other machinery---to a check roughly likeCircle::classof(S)
. For more information, see :ref:`classof-contract`.The argument to
classof
should always be an ancestor class because the implementation has logic to allow and optimize away upcasts/up-isa<>
's automatically. It is as though every classFoo
automatically has aclassof
like:classFoo { [...] template <classT> staticboolclassof(const T *, ::std::enable_if< ::std::is_base_of<Foo, T>::value >::type* = 0) { returntrue; } [...] };
Note that this is the reason that we did not need to introduce a
classof
intoShape
: all relevant classes derive fromShape
, andShape
itself is abstract (has no entry in theKind
enum), so this notional inferredclassof
is all we need. See Concrete Bases and Deeper Hierarchies for more information about how to extend this example to more general hierarchies.
Although for this small example setting up LLVM-style RTTI seems like a lot of "boilerplate", if your classes are doing anything interesting then this will end up being a tiny fraction of the code.
For concrete bases (i.e. non-abstract interior nodes of the inheritance tree), the Kind
check inside classof
needs to be a bit more complicated. The situation differs from the example above in that
- Since the class is concrete, it must itself have an entry in the
Kind
enum because it is possible to have objects with this class as a dynamic type. - Since the class has children, the check inside
classof
must take them into account.
Say that SpecialSquare
and OtherSpecialSquare
derive from Square
, and so ShapeKind
becomes:
enum ShapeKind { SK_Square, + SK_SpecialSquare, + SK_OtherSpecialSquare, SK_Circle }
Then in Square
, we would need to modify the classof
like so:
- staticboolclassof(const Shape *S) { - return S->getKind() == SK_Square; - } + staticboolclassof(const Shape *S) { + return S->getKind() >= SK_Square && + S->getKind() <= SK_OtherSpecialSquare; + }
The reason that we need to test a range like this instead of just equality is that both SpecialSquare
and OtherSpecialSquare
"is-a" Square
, and so classof
needs to return true
for them.
This approach can be made to scale to arbitrarily deep hierarchies. The trick is that you arrange the enum values so that they correspond to a preorder traversal of the class hierarchy tree. With that arrangement, all subclass tests can be done with two comparisons as shown above. If you just list the class hierarchy like a list of bullet points, you'll get the ordering right:
| Shape | Square | SpecialSquare | OtherSpecialSquare | Circle
The example just given opens the door to bugs where the classof
s are not updated to match the Kind
enum when adding (or removing) classes to (from) the hierarchy.
Continuing the example above, suppose we add a SomewhatSpecialSquare
as a subclass of Square
, and update the ShapeKind
enum like so:
enum ShapeKind { SK_Square, SK_SpecialSquare, SK_OtherSpecialSquare, + SK_SomewhatSpecialSquare, SK_Circle }
Now, suppose that we forget to update Square::classof()
, so it still looks like:
staticboolclassof(const Shape *S) { // BUG: Returns false when S->getKind() == SK_SomewhatSpecialSquare,// even though SomewhatSpecialSquare "is a" Square.return S->getKind() >= SK_Square && S->getKind() <= SK_OtherSpecialSquare; }
As the comment indicates, this code contains a bug. A straightforward and non-clever way to avoid this is to introduce an explicit SK_LastSquare
entry in the enum when adding the first subclass(es). For example, we could rewrite the example at the beginning of Concrete Bases and Deeper Hierarchies as:
enum ShapeKind { SK_Square, + SK_SpecialSquare, + SK_OtherSpecialSquare, + SK_LastSquare, SK_Circle } ... // Square::classof() - staticboolclassof(const Shape *S) { - return S->getKind() == SK_Square; - } + staticboolclassof(const Shape *S) { + return S->getKind() >= SK_Square && + S->getKind() <= SK_LastSquare; + }
Then, adding new subclasses is easy:
enum ShapeKind { SK_Square, SK_SpecialSquare, SK_OtherSpecialSquare, + SK_SomewhatSpecialSquare, SK_LastSquare, SK_Circle }
Notice that Square::classof
does not need to be changed.
To be more precise, let classof
be inside a class C
. Then the contract for classof
is "return true
if the dynamic type of the argument is-a C
". As long as your implementation fulfills this contract, you can tweak and optimize it as much as you want.
For example, LLVM-style RTTI can work fine in the presence of multiple-inheritance by defining an appropriate classof
. An example of this in practice is Decl vs. DeclContext inside Clang. The Decl
hierarchy is done very similarly to the example setup demonstrated in this tutorial. The key part is how to then incorporate DeclContext
: all that is needed is in bool DeclContext::classof(const Decl *)
, which asks the question "Given a Decl
, how can I determine if it is-a DeclContext
?". It answers this with a simple switch over the set of Decl
"kinds", and returning true for ones that are known to be DeclContext
's.
.. TODO:: Touch on some of the more advanced features, like ``isa_impl`` and ``simplify_type``. However, those two need reference documentation in the form of doxygen comments as well. We need the doxygen so that we can say "for full details, see https://llvm.org/doxygen/..."
- The
Kind
enum should have one entry per concrete class, ordered according to a preorder traversal of the inheritance tree. - The argument to
classof
should be aconst Base *
, whereBase
is some ancestor in the inheritance hierarchy. The argument should never be a derived class or the class itself: the template machinery forisa<>
already handles this case and optimizes it. - For each class in the hierarchy that has no children, implement a
classof
that checks only against itsKind
. - For each class in the hierarchy that has children, implement a
classof
that checks a range of the first child'sKind
and the last child'sKind
.
Sometimes it is not possible to know all types in a hierarchy ahead of time. For example, in the shapes hierarchy described above the authors may have wanted their code to work for user defined shapes too. To support use cases that require open hierarchies LLVM provides the RTTIRoot
and RTTIExtends
utilities.
The RTTIRoot
class describes an interface for performing RTTI checks. The RTTIExtends
class template provides an implementation of this interface for classes derived from RTTIRoot
. RTTIExtends
uses the "Curiously Recurring Template Idiom", taking the class being defined as its first template argument and the parent class as the second argument. Any class that uses RTTIExtends
must define a static char ID
member, the address of which will be used to identify the type.
This open-hierarchy RTTI support should only be used if your use case requires it. Otherwise the standard LLVM RTTI system should be preferred.
E.g.
classShape : publicRTTIExtends<Shape, RTTIRoot> { public:staticchar ID; virtualdoublecomputeArea() = 0; }; classSquare : publicRTTIExtends<Square, Shape> { double SideLength; public:staticchar ID; Square(double S) : SideLength(S) {} doublecomputeArea() override; }; classCircle : publicRTTIExtends<Circle, Shape> { double Radius; public:staticchar ID; Circle(double R) : Radius(R) {} doublecomputeArea() override; }; char Shape::ID = 0; char Square::ID = 0; char Circle::ID = 0;
The underlying implementation of isa/cast/dyn_cast is all controlled through a struct called CastInfo
. CastInfo
provides 4 methods, isPossible
, doCast
, castFailed
, and doCastIfPossible
. These are for isa
, cast
, and dyn_cast
, in order. You can control the way your cast is performed by creating a specialization of the CastInfo
struct (to your desired types) that provides the same static methods as the base CastInfo
struct.
This can be a lot of boilerplate, so we also have what we call Cast Traits. These are structs that provide one or more of the above methods so you can factor out common casting patterns in your project. We provide a few in the header file ready to be used, and we'll show a few examples motivating their usage. These examples are not exhaustive, and adding new cast traits is easy so users should feel free to add them to their project, or contribute them if they're particularly useful!
In this case, we have a struct that is what we call 'nullable' - i.e. it is constructible from nullptr
and that results in a value you can tell is invalid.
classSomeValue { public:SomeValue(void *ptr) : ptr(ptr) {} void *getPointer() const { return ptr; } boolisValid() const { return ptr != nullptr; } private:void *ptr; };
Given something like this, we want to pass this object around by value, and we would like to cast from objects of this type to some other set of objects. For now, we assume that the types we want to cast to all provide classof
. So we can use some provided cast traits like so:
template <typename T> structCastInfo<T, SomeValue> : CastIsPossible<T, SomeValue>, NullableValueCastFailed<T>, DefaultDoCastIfPossible<T, SomeValue, CastInfo<T, SomeValue>> { static T doCast(SomeValue v) { returnT(v.getPointer()); } };
Now given the value above SomeValue
, maybe we'd like to be able to cast to that type from a char pointer type. So what we would do in that case is:
template <typename T> structCastInfo<SomeValue, T *> : NullableValueCastFailed<SomeValue>, DefaultDoCastIfPossible<SomeValue, T *, CastInfo<SomeValue, T *>> { staticboolisPossible(const T *t) { return std::is_same<T, char>::value; } static SomeValue doCast(const T *t) { returnSomeValue((void *)t); } };
This would enable us to cast from a char *
to a SomeValue, if we wanted to.
When your types are not constructible from nullptr
or there isn't a simple way to tell when an object is invalid, you may want to use std::optional
. In those cases, you probably want something like this:
template <typename T> structCastInfo<T, SomeValue> : OptionalValueCast<T, SomeValue> {};
That cast trait requires that T
is constructible from const SomeValue &
but it enables casting like so:
SomeValue someVal = ...; std::optional<AnotherValue> valOr = dyn_cast<AnotherValue>(someVal);
With the _if_present
variants, you can even do optional chaining like this:
std::optional<SomeValue> someVal = ...; std::optional<AnotherValue> valOr = dyn_cast_if_present<AnotherValue>(someVal);
and valOr
will be std::nullopt
if either someVal
cannot be converted or if someVal
was also std::nullopt
.