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Plotly's Python library is free and open source! Get started by downloading the client and reading the primer.
You can set up Plotly to work in online or offline mode, or in jupyter notebooks.
We also have a quick-reference cheatsheet (new!) to help you get started!
The tutorial below imports NumPy, Pandas, SciPy, and Statsmodels.
importplotly.plotlyaspyimportplotly.graph_objsasgofromplotly.toolsimportFigureFactoryasFFimportnumpyasnpimportpandasaspdimportscipyimportstatsmodelsimportstatsmodels.apiassmfromstatsmodels.formula.apiimportols
An Analysis of Variance Test
or an ANOVA
is a generalization of the t-tests to more than 2 groups. Our null hypothesis states that there are equal means in the populations from which the groups of data were sampled. More succinctly:
for
moore=sm.datasets.get_rdataset("Moore", "car", cache=True) data=moore.datadata=data.rename(columns={"partner.status" :"partner_status"}) # make name pythonicmoore_lm=ols('conformity ~ C(fcategory, Sum)*C(partner_status, Sum)', data=data).fit() table=sm.stats.anova_lm(moore_lm, typ=2) # Type 2 ANOVA DataFrameprint(table)
In this ANOVA test, we are dealing with an F-Statistic
and not a p-value
. Their connection is integral as they are two ways of expressing the same thing. When we set a significance level
at the start of our statistical tests (usually 0.05), we are saying that if our variable in question takes on the 5% ends of our distribution, then we can start to make the case that there is evidence against the null, which states that the data belongs to this particular distribution.
The F value is the point such that the area of the curve past that point to the tail is just the p-value. Therefore:
For more information on the choice of 0.05 for a significance level, check out this page.
Let us import some data for our next analysis. This time some data on tooth growth:
data=pd.read_csv('https://raw.githubusercontent.com/plotly/datasets/master/tooth_growth_csv') df=data[0:10] table=FF.create_table(df) py.iplot(table, filename='tooth-data-sample')
In a Two-Way ANOVA
, there are two variables to consider. The question is whether our variable in question (tooth length len
) is related to the two other variables supp
and dose
by the equation:
formula='len ~ C(supp) + C(dose) + C(supp):C(dose)'model=ols(formula, data).fit() aov_table=statsmodels.stats.anova.anova_lm(model, typ=2) print(aov_table)
fromIPython.displayimportdisplay, HTMLdisplay(HTML('<link href="//fonts.googleapis.com/css?family=Open+Sans:600,400,300,200|Inconsolata|Ubuntu+Mono:400,700" rel="stylesheet" type="text/css" />')) display(HTML('<link rel="stylesheet" type="text/css" href="http://help.plot.ly/documentation/all_static/css/ipython-notebook-custom.css">')) ! pipinstallgit+https://github.com/plotly/publisher.git--upgradeimportpublisherpublisher.publish( 'python-Anova.ipynb', 'python/anova/', 'Anova | plotly', 'Learn how to perform a one and two way ANOVA test using Python.', title='Anova in Python | plotly', name='Anova', language='python', page_type='example_index', has_thumbnail='false', display_as='statistics', order=8, ipynb='~notebook_demo/108')