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sol1.py
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"""
Self Powers
Problem 48
The series, 1^1 + 2^2 + 3^3 + ... + 10^10 = 10405071317.
Find the last ten digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.
"""
defsolution():
"""
Returns the last 10 digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.
>>> solution()
'9110846700'
"""
total=0
foriinrange(1, 1001):
total+=i**i
returnstr(total)[-10:]
if__name__=="__main__":
print(solution())
