We are given a list nums of integers representing a list compressed with run-length encoding.

Consider each adjacent pair of elements [freq, val] = [nums[2*i], nums[2*i+1]] (with i >= 0). For each such pair, there are freq elements with value val concatenated in a sublist. Concatenate all the sublists from left to right to generate the decompressed list.

Return the decompressed list.

Example 1:

Input: nums = [1,2,3,4] Output: [2,4,4,4] Explanation: The first pair [1,2] means we have freq = 1 and val = 2 so we generate the array [2]. The second pair [3,4] means we have freq = 3 and val = 4 so we generate [4,4,4]. At the end the concatenation [2] + [4,4,4] is [2,4,4,4]. 

Example 2:

Input: nums = [1,1,2,3] Output: [1,3,3] 

Constraints:

• 2 <= nums.length <= 100
• nums.length % 2 == 0
• 1 <= nums[i] <= 100

给你一个以行程长度编码压缩的整数列表 nums 。考虑每对相邻的两个元素 [freq, val] = [nums[2i], nums[2i+1]] （其中 i >= 0 ），每一对都表示解压后子列表中有 freq 个值为 val 的元素，你需要从左到右连接所有子列表以生成解压后的列表。请你返回解压后的列表。

• 给定一个带编码长度的数组，要求解压这个数组。
• 简单题。按照题目要求，下标从 0 开始，奇数位下标为前一个下标对应元素重复次数，那么就把这个元素 append 几次。最终输出解压后的数组即可。

package leetcode funcdecompressRLElist(nums []int) []int { res:= []int{} fori:=0; i<len(nums); i+=2 { forj:=0; j<nums[i]; j++ { res=append(res, nums[i+1]) } } returnres }