Skip to content

Latest commit

 

History

History

0559.Maximum-Depth-of-N-ary-Tree

题目

Given a n-ary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).

Example 1:

https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png

Input: root = [1,null,3,2,4,null,5,6] Output: 3 

Example 2:

https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png

Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] Output: 5 

Constraints:

  • The total number of nodes is in the range [0, 10000].
  • The depth of the n-ary tree is less than or equal to 1000.

题目大意

给定一个 N 叉树,找到其最大深度。

最大深度是指从根节点到最远叶子节点的最长路径上的节点总数。

N 叉树输入按层序遍历序列化表示,每组子节点由空值分隔(请参见示例)。

解题思路

  • 使用广度优先遍历

代码

package leetcode typeNodestruct { ValintChildren []*Node } funcmaxDepth(root*Node) int { ifroot==nil { return0 } return1+bfs(root) } funcbfs(root*Node) int { varq []*Nodevardepthintq=append(q, root.Children...) forlen(q) !=0 { depth++length:=len(q) forlength!=0 { ele:=q[0] q=q[1:] length--ifele!=nil&&len(ele.Children) !=0 { q=append(q, ele.Children...) } } } returndepth }
close