Given two strings representing two complex numbers.

You need to return a string representing their multiplication. Note i2 = -1 according to the definition.

Example 1:

Input: "1+1i", "1+1i" Output: "0+2i" Explanation: (1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i, and you need convert it to the form of 0+2i. 

Example 2:

Input: "1+-1i", "1+-1i" Output: "0+-2i" Explanation: (1 - i) * (1 - i) = 1 + i2 - 2 * i = -2i, and you need convert it to the form of 0+-2i. 

Note:

1. The input strings will not have extra blank.
2. The input strings will be given in the form of a+bi, where the integer a and b will both belong to the range of [-100, 100]. And the output should be also in this form.

给定两个表示复数的字符串。返回表示它们乘积的字符串。注意，根据定义 i^2 = -1 。

注意:

• 输入字符串不包含额外的空格。
• 输入字符串将以 a+bi 的形式给出，其中整数 a 和 b 的范围均在 [-100, 100] 之间。输出也应当符合这种形式。

• 给定 2 个字符串，要求这两个复数的乘积，输出也是字符串格式。
• 数学题。按照复数的运算法则，i^2 = -1，最后输出字符串结果即可。

package leetcode import ( "strconv""strings" ) funccomplexNumberMultiply(astring, bstring) string { realA, imagA:=parse(a) realB, imagB:=parse(b) real:=realA*realB-imagA*imagBimag:=realA*imagB+realB*imagAreturnstrconv.Itoa(real) +"+"+strconv.Itoa(imag) +"i" } funcparse(sstring) (int, int) { ss:=strings.Split(s, "+") r, _:=strconv.Atoi(ss[0]) i, _:=strconv.Atoi(ss[1][:len(ss[1])-1]) returnr, i }