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logical-and-struct.md

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Learn more about: logical_and Struct
logical_and Struct
11/04/2016
functional/std::logical_and
logical_and class
logical_and struct
1a375cc2-0592-4d57-a553-78009c7ad610

logical_and Struct

A predefined function object that performs the logical conjunction operation (operator&&) on its arguments.

Syntax

template <classType = void> structlogical_and : publicbinary_function<Type, Type, bool> { booloperator()(const Type& Left, const Type& Right) const; }; // specialized transparent functor for operator&&template <> structlogical_and<void> { template <classT, classU> autooperator()(T&& Left, U&& Right) const -> decltype(std::forward<T>(Left) && std::forward<U>(Right)); };

Parameters

Type, T, U
Any type that supports an operator&& that takes operands of the specified or inferred types.

Left
The left operand of the logical conjunction operation. The unspecialized template takes an lvalue reference argument of type Type. The specialized template does perfect forwarding of lvalue and rvalue reference arguments of inferred type T.

Right
The right operand of the logical conjunction operation. The unspecialized template takes an lvalue reference argument of type Type. The specialized template does perfect forwarding of lvalue and rvalue reference arguments of inferred type U.

Return Value

The result of Left && Right. The specialized template does perfect forwarding of the result, which has the type that's returned by operator&&.

Remarks

For user-defined types, there is no short-circuiting of operand evaluation. Both arguments are evaluated by operator&&.

Example

// functional_logical_and.cpp// compile with: /EHsc #define_CRT_RAND_S #include<stdlib.h> #include<deque> #include<algorithm> #include<functional> #include<iostream>intmain( ) { usingnamespacestd; deque<bool> d1, d2, d3( 7 ); deque<bool>::iterator iter1, iter2, iter3; unsignedint randomValue; int i; for ( i = 0 ; i < 7 ; i++ ) { if ( rand_s( &randomValue ) == 0 ) { d1.push_back((bool)(( randomValue % 2 ) != 0)); } } int j; for ( j = 0 ; j < 7 ; j++ ) { if ( rand_s( &randomValue ) == 0 ) { d2.push_back((bool)(( randomValue % 2 ) != 0)); } } cout << boolalpha; // boolalpha I/O flag on cout << "Original deque:\n d1 = ( " ; for ( iter1 = d1.begin( ) ; iter1 != d1.end( ) ; iter1++ ) cout << *iter1 << ""; cout << ")" << endl; cout << "Original deque:\n d2 = ( " ; for ( iter2 = d2.begin( ) ; iter2 != d2.end( ) ; iter2++ ) cout << *iter2 << ""; cout << ")" << endl; // To find element-wise conjunction of the truth values// of d1 & d2, use the logical_and function objecttransform( d1.begin( ), d1.end( ), d2.begin( ), d3.begin( ), logical_and<bool>( ) ); cout << "The deque which is the conjunction of d1 & d2 is:\n d3 = ( " ; for ( iter3 = d3.begin( ) ; iter3 != d3.end( ) ; iter3++ ) cout << *iter3 << ""; cout << ")" << endl; }
Original deque: d1 = ( true true true true true false false ) Original deque: d2 = ( true false true true false true false ) The deque which is the conjunction of d1 & d2 is: d3 = ( true false true true false false false ) 
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