description | title | ms.date | helpviewer_keywords | ms.assetid | |
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Learn more about: constexpr lambda expressions in C++ | constexpr lambda expressions in C++ | 04/08/2019 |
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Visual Studio 2017 version 15.3 and later (available in /std:c++17
mode and later): A lambda expression may be declared as constexpr
or used in a constant expression when the initialization of each data member that it captures or introduces is allowed within a constant expression.
int y = 32; auto answer = [y]() constexpr { int x = 10; return y + x; }; constexprintIncrement(int n) { return [n] { return n + 1; }(); }
A lambda is implicitly constexpr
if its result satisfies the requirements of a constexpr
function:
auto answer = [](int n) { return32 + n; }; constexprint response = answer(10);
If a lambda is implicitly or explicitly constexpr
, and you convert it to a function pointer, the resulting function is also constexpr
:
auto Increment = [](int n) { return n + 1; }; constexprint(*inc)(int) = Increment;
C++ Language Reference
Function Objects in the C++ Standard Library
Function Callfor_each