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solution.cpp
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
classSolution {
public:
intcountPairs(TreeNode* root, int distance) {
unordered_map<TreeNode *, unordered_set<TreeNode *>> g;
unordered_set<TreeNode *> leaves;
build(root, nullptr, g, leaves);
int ans = 0;
for(auto u : leaves) {
queue<TreeNode *> q;
unordered_set<TreeNode *> seen;
int tmp = distance + 1;
q.push(u);
while(tmp--) {
int sz = q.size();
while(sz--) {
auto t = q.front();
q.pop();
if(leaves.count(t) && t != u)
ans++;
if(seen.count(t))
continue;
seen.insert(t);
for(auto v : g[t])
q.push(v);
}
}
}
return ans / 2;
}
private:
voidbuild(
TreeNode *root,
TreeNode *p,
unordered_map<TreeNode *, unordered_set<TreeNode *>> &g,
unordered_set<TreeNode *> &leaves
) {
if(!root)
return;
if(!g.count(root))
g[root] = {};
if(p) {
g[p].insert(root);
g[root].insert(p);
}
if(!root->left && !root->right) {
leaves.insert(root);
return;
}
if(root->left)
build(root->left, root, g, leaves);
if(root->right)
build(root->right, root, g, leaves);
}
voiddfs(
unordered_map<TreeNode *, unordered_set<TreeNode *>> &g,
TreeNode *u,
TreeNode *v,
unordered_set<TreeNode *> &seen,
int &ans,
int d
) {
if(seen.count(u))
return;
if(d < 0)
return;
if(u == v) {
if(d >= 0)
ans++;
return;
}
seen.insert(u);
d--;
for(auto w : g[u])
dfs(g, w, v, seen, ans, d);
}
};