1027-longest-arithmetic-sequence.py

"""
Problem Link: https://leetcode.com/problems/longest-arithmetic-sequence/

Given an array A of integers, return the length of the longest arithmetic subsequence in A.
Recall that a subsequence of A is a list A[i_1], A[i_2], ..., A[i_k] with 
0 <= i_1 < i_2 < ... < i_k <= A.length - 1, and that a sequence B is arithmetic if B[i+1] - B[i] 
are all the same value (for 0 <= i < B.length - 1).

Example 1:
Input: [3,6,9,12]
Output: 4
Explanation: 
The whole array is an arithmetic sequence with steps of length = 3.

Example 2:
Input: [9,4,7,2,10]
Output: 3
Explanation: 
The longest arithmetic subsequence is [4,7,10].

Example 3:
Input: [20,1,15,3,10,5,8]
Output: 4
Explanation: 
The longest arithmetic subsequence is [20,15,10,5].

Note:
2 <= A.length <= 2000
0 <= A[i] <= 10000
"""
# Time Complexity: O(n^2)
# Space Complexity: O(n^2)
importcollections
classSolution:
deflongestArithSeqLength(self, A: List[int]) ->int:
dp=collections.defaultdict(dict)
maxLength=1
foriinrange(1,len(A)):
forjinrange(i):
diff=A[i] -A[j]
dp[i][diff] =1+dp[j].get(diff, 1)
maxLength=max(maxLength, dp[i][diff])
returnmaxLength

classSolution1:
deflongestArithSeqLength(self, A: List[int]) ->int:
dp= {}
foriinrange(len(A)):
forjinrange(i+1, len(A)):
diff=A[j] -A[i]
dp[j, diff] =dp.get((i, diff), 1) +1
returnmax(dp.values())