- Notifications
You must be signed in to change notification settings - Fork 19.9k
/
Copy pathKaprekarNumbers.java
53 lines (46 loc) · 2.12 KB
/
KaprekarNumbers.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
packagecom.thealgorithms.maths;
importjava.math.BigInteger;
importjava.util.ArrayList;
importjava.util.List;
publicfinalclassKaprekarNumbers {
privateKaprekarNumbers() {
}
/* This program demonstrates if a given number is Kaprekar Number or not.
Kaprekar Number: A Kaprekar number is an n-digit number which its square can be split into
two parts where the right part has n digits and sum of these parts is equal to the original
number. */
// Provides a list of kaprekarNumber in a range
publicstaticList<Long> kaprekarNumberInRange(longstart, longend) throwsException {
longn = end - start;
if (n < 0) {
thrownewException("Invalid range");
}
ArrayList<Long> list = newArrayList<>();
for (longi = start; i <= end; i++) {
if (isKaprekarNumber(i)) {
list.add(i);
}
}
returnlist;
}
// Checks whether a given number is Kaprekar Number or not
publicstaticbooleanisKaprekarNumber(longnum) {
Stringnumber = Long.toString(num);
BigIntegeroriginalNumber = BigInteger.valueOf(num);
BigIntegernumberSquared = originalNumber.multiply(originalNumber);
if (number.length() == numberSquared.toString().length()) {
returnnumber.equals(numberSquared.toString());
} else {
BigIntegerleftDigits1 = BigInteger.ZERO;
BigIntegerleftDigits2;
if (numberSquared.toString().contains("0")) {
leftDigits1 = newBigInteger(numberSquared.toString().substring(0, numberSquared.toString().indexOf("0")));
}
leftDigits2 = newBigInteger(numberSquared.toString().substring(0, (numberSquared.toString().length() - number.length())));
BigIntegerrightDigits = newBigInteger(numberSquared.toString().substring(numberSquared.toString().length() - number.length()));
Stringx = leftDigits1.add(rightDigits).toString();
Stringy = leftDigits2.add(rightDigits).toString();
return (number.equals(x)) || (number.equals(y));
}
}
}